## Question

Find the equations of the line parallel to 5*x* – 12*y* + 26 = 0 and at a distance of 4 units from it.

### Solution

5*x* – 12*y* – 26 = 0 and 5*x* – 12*y* + 78 = 0

Equation of any line parallel to 5*x* – 12*y* + 26 = 0 is

5*x* – 12*y* + λ = 0 …(i)

Since the distance between the parallel lines is 4 units, them

Substituting the values of λ in (i), we get

5*x* – 12*y* – 26 = 0 and 5*x* – 12*y* + 78 = 0

#### SIMILAR QUESTIONS

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